Valence
Bond Theory
Another topic that you’ll
need to be familiar with for the SAT II Chemistry test is that of valence bond
theory. By now, you are aware that two atoms will form a bond when there is
orbital overlap between them, and a maximum of two electrons can be present in
the overlapping orbitals.
Since the pair of electrons
is attracted to both atomic nuclei, a bond is formed, and as the extent of
overlap increases, the strength of the bond increases. The electronic energy
drops as the atoms approach each other, but it begins to increase again when
they become too close. This means there is an optimum distance, the observed
bond distance, at which the total energy is at a minimum.
Let’s delve a little more
deeply into sigma bonds now and describe them in more detail. As you know,
sigma (s) bonds are single bonds. They result from the overlap of two s orbitals, an s and a p orbital, or two head-to-head p orbitals. The electron density of a sigma bond
is greatest along the axis of the bond. Maximum overlap forms the strongest-possible
sigma bond, and the two atoms will arrange themselves to give the
greatest-possible orbital overlap. This is tricky with p orbitals since they are directional along
the x, y, and z axes.
Hybrid orbitals result
from a blending of atomic orbitals (in other words, s and porbitals) to create
orbitals that have energy that’s in between the energy of the lone orbitals.
Look at the methane molecule, for example: all four of the C—H bonds are 109.5Âş
apart, while nonbonded p orbitals are
only 90Âş apart.
The orbitals shown at the
left of the figure are for a nonbonded carbon atom, but once the carbon atom
begins to bond with other atoms (in this case hydrogen), the atomic orbitals
hybridize, and this changes their shape considerably. Notice how the first set
of figures form the sp3 atomic orbital, the hybrid, and this leads to
further hybridization.
Ammonia also has sp3 hybridization,
even though it has a lone pair.
Multiple
Bonding
Now let’s look more closely
at pi bonds. As we mentioned earlier in this chapter, pi (p) bonds result from
the sideways overlap of p orbitals, and
pi orbitals are defined by the region above and below an imaginary line
connecting the nuclei of the two atoms. Keep in mind that pi bonds never occur
unless a sigma bond has formed first, and they may form only if
unhybridized p orbitals remain on the
bonded atoms. Also, they occur when sp or sp2 hybridization
is present on central atom but not sp3hybridization.
Below, we show the
formation of a set of sp2 orbitals. This molecule would contain a double
bond, like ethene. Notice again how the first set of figures form the sp2 atomic
orbital, the hybrid, and the last figure shows full hybridization:
The set of p orbitals that are unhybridized are not shown in
this depiction:
A different view, which
doesn’t show the hydrogens and centers on the C atoms, shows the
unhybridized p orbitals that create the
sideways overlap that’s necessary to create the double pi bond:
Here’s how it looks with
all the pieces put together:
Here is a table summarizing
hybridization and structure:
effective
pairs
|
hybridization
|
geometry
|
||
2
|
Sp
|
linear
|
|
|
3
|
sp2
|
trigonal planar
|
|
|
4
|
sp3
|
tetrahedral
|
|
|
5
|
dsp3
|
trigonal bipyramidal
|
|
|
6
|
d2sp3
|
octahedral
|
|
|
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